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10x^2+110x+240=0
a = 10; b = 110; c = +240;
Δ = b2-4ac
Δ = 1102-4·10·240
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-50}{2*10}=\frac{-160}{20} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+50}{2*10}=\frac{-60}{20} =-3 $
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